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BA30E00WHFP-TR Scheda tecnica(PDF) 11 Page - Rohm

Il numero della parte BA30E00WHFP-TR
Spiegazioni elettronici  Dual-Output (Fixed/Variable) LDO Regulators
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Produttore elettronici  ROHM [Rohm]
Homepage  http://www.rohm.com
Logo ROHM - Rohm

BA30E00WHFP-TR Scheda tecnica(HTML) 11 Page - Rohm

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BA3259HFP
BA30E00WHFP
Datasheet
TSZ02201-0R6R0A600100-1-2
26.Jun.2012 Rev.001
www.rohm.com
© 2012 ROHM Co., Ltd. All rights reserved.
TSZ22111・15・001
Application Information
●Setting the Output Voltage Vo2
The following output voltage setting method applies to the variable output pin.
Vo2=VADJ
× ( 1 +
R2
) - R2
× IADJ
R1
VADJ: Output feedback reference voltage
(0.8 V typ.)
IADJ: ADJ pin source current
(0.05µA typ.: BA3259HFP)
(0.2µA typ.: BA30E00WHFP)
Note:Connect R1 and R2 to make output voltage settings as shown in Fig.1and Fig.2. Keep in mind that the offset
voltage caused by the current (IADJ) flowing out of the ADJ pin will become high if higher resistance is used.
●Function Explanation
1) Two-input power supply (BA30E00WHFP)
The input voltages (Vcc1 and Vcc2) supply power to two outputs (Vo1 and Vo2, respectively). The power dissipation
between the input and output pins can be suppressed for each output according to usage.
2) Standby function (BA30E00WHFP)
The standby function is operated through the EN pin. Output is turned on at 2.0 V or higher and turned off at 0.8 V or
lower.
●Power Dissipation
If the IC is used under the conditions of excess of the power dissipation, the chip temperature will rise, which will have an
adverse effect on the electrical characteristics of the IC, such as a reduction in current capability. Furthermore, if the
temperature exceeds Tjmax, element deterioration or damage may occur. Implement proper thermal designs to ensure that
the power dissipation is within the permissible range in order to prevent instantaneous IC damage resulting from heat and
maintain the reliability of the IC for long-term operation. Refer to the power derating characteristics curves in Fig.27.
・Power Consumption Pc (W) Calculation Method:
○BA3259HFP
○BA30E00WHFP
5V
Vcc
Vo1
Vo2
REG1
REG2
3.3 V/0.3 A
1.8 V/0.3 A
Power loss between input and output
(Vcc
− Vo1)
× Io1 + (Vcc − Vo2) × Io2
= (5
− 3.3)
× 0.3 + (5 − 1.8) × 0.3
= 0.51W + 0.96W
= 1.47W
→ Single 5V input results in decreased
efficiency
Power loss between input and output
(Vcc1
− Vo1)
× Io1 + (Vcc2 − Vo2) × Io2
= (5
− 3.3)
× 0.3 + (5 − 1.8) × 0.3
= 0.51W + 0.36W
= 0.87W
Reduced power loss by
0.6W.
→ Additional 3V input improves efficiency
5V
Vcc
Vo1
Vo2
REG1
REG2
3V
3.3 V/0.3 A
1.8 V/0.3 A
Conventional
Efficiency comparison:
5V single input vs. 5V/3V two inputs
•Regulator with single input and two outputs
•Regulator with two inputs and two outputs
(Vo2=1.8V, Io1=Io2=0.3A)
Current
Vcc
GND
Vo1
Vo2
Controller
Icc
IP
Vcc
Vcc
Io1
Io2
3.3 V
output
0.8 V to
3.3 V
output
Power
Tr
Power
Tr
Vcc1
GND
Io1
Io2
Controller
Icc1+Icc2
Vcc1
Vcc2
Io1
Io2
3.3 V
output
0.8 V to
3.3 V
output
Vcc2
IB1
IB2
Power
Tr
Power
Tr
• Power consumption of power transistor on
Vo1 (3.3 V output)
Pc1=(Vcc1
− Vo1)
× Io1
• Power consumption of power transistor on
Vo2 (variable output )
Pc2=(Vcc2
− Vo2)
× Io2
• Power consumption by circuit current
Pc3=Vcc1
× Icc1 + Vcc2 × Icc2
Pc=Pc1 + Pc2 + Pc3
* Vcc1, Vcc2: Applied voltage
Io1: Load current on 3.3 V output side
Io2: Load current on variable output side
Icc1, Icc2:
Circuit currents
• Power consumption of 3.3 V power
transistor
Pc1=(Vcc
− 3.3)
× Io1
• Power consumption of Vo2 power
transistor
Pc2=(Vcc
− Vo2)
× Io2
• Power consumption by circuit current
Pc3=Vcc
× Icc
Pc=Pc1 + Pc2 + Pc3
* Vcc: Applied voltage
Io1: Load current on Vo1 side
Io2: Load current on Vo2 side
Icc: Circuit current
R1
BA3259HFP: 1 kΩ to 10 kΩ
BA30E00HFP: 1 kΩ to 5 kΩ
The above is recommended.
Vo2
ADJ
IADJ
VADJ
R2
R1


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